The ratio of charge densities on the surface of two conducting spheres is 3 : 2. lithe radii of t: the spheres are 4 cm and 8 cm the ratio of the electric potential on the surfaces of the sphere 2 is
3 : 4
3 : 1
1 : 3
4 : 9

Question

The ratio of charge densities on the surface of two conducting spheres is 3 : 2. lithe radii of t: the spheres are 4 cm and 8 cm the ratio of the electric potential on the surfaces of the sphere 2 is
3 : 4
3 : 1
1 : 3
4 : 9

Toppr Admin · Accepted Answer

Ratio of charge densities -3-2 spheres are 4cm and 8cmspheres ratio -4-8-1-2E1-E2-E -x3B1-xA0-x3BB-rE1E2-x3BB-1-x3BB-2-xD7-r2r1-xA0- -xA0- -xA0- -xA0-32-xD7-21-xA0- -xA0- -xA0- -xA0-3-1E2-E1-1-3

The ratio of charge densities on the surface of two conducting spheres is 3 : 2. lithe radii of t: the spheres are 4 cm and 8 cm the ratio of the electric potential on the surfaces of the sphere 2 is3 : 43 : 11 : 34 : 9

Ratio of charge densities =3:2 spheres are 4cm and 8cmspheres ratio =4:8=1:2E1:E2=?E α λrE1E2=λ1λ2×r2r1 =32×21 =3:1E2:E1=1:3

The ratio of charge densities on the surface of two conducting spheres is 3 : 2. lithe radii of t: the spheres are 4 cm and 8 cm the ratio of the electric potential on the surfaces of the sphere 2 is
3 : 4
3 : 1
1 : 3
4 : 9

Ratio of charge densities $= 3 : 2$ spheres are $4 c m$ and $8 c m$
spheres ratio $= 4 : 8 = 1 : 2$
$E_{1} : E_{2} = ?$
$E$ $α$ $\frac{λ}{r}$
$\frac{E_{1}}{E_{2}} = \frac{λ_{1}}{λ_{2}} \times \frac{r_{2}}{r_{1}}$
$= \frac{3}{2} \times \frac{2}{1}$
$= 3 : 1$
$E_{2} : E_{1} = 1 : 3$