The ratio of electric force to the gravitational force between two protons separated by a finite distance is of the order of:

10^{- 19}

10^{+ 19}

10^{- 36}

10^{+ 36}

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Solution

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$G r a v i t a t i o n a l f o r c e = \frac{G (m_{p})^{2}}{r^{2}}$
$E l e c t r i c f o r c e = \frac{K (e) (e)}{r^{2}}$
$R a t i o = \frac{K (1.6 \times 10^{- 19})^{2}}{r^{2}} \times \frac{r^{2}}{G \times (1.6 7 \times 10^{- 27})^{2}}$
$= \frac{(9 \times 10^{9}) \times (1.6 \times 10^{- 19})^{2}}{(6.6 7 \times 10^{- 11}) (1.6 7 \times 10^{- 27})^{2}}$
$= 1.23 \times 10^{20} \times 10^{16}$
$= 10^{36}$ (order of magnitude)

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The ratio of electric force to the gravitational force between two protons separated by a finite distance is of the order of:

Gravitational force =G(mp)2r2Electric force =K(e)(e)r2Ratio =K(1.6×10−19)2r2×r2G×(1.6 7×10−27)2=(9×109)×(1.6×10−19)2(6.6 7×10−11)(1.6 7×10−27)2=1.23×1020×1016=1036(order of magnitude)