Question

The ratio of length of two trains is $5:3$ and the ratio of their speed is $6:5$. The ratio of time taken by them to cross a pole is

• A. $5:6$
• B. $11:8$
• C. $25:18$
• D. $27:16$

Answer 1

Answer: (C)

It is given that,
$\frac{l_1}{l_2}=\frac{5}{3}$ and $\frac{s_1}{s_2}=\frac{6}{5}\Rightarrow \frac{t_1}{t_2}=\frac{\frac{l_1}{s_1}}{\frac{l_2}{s_2}}=\frac{l_1}{l_2}\times \frac{s_2}{s_1}=\frac{5}{3}\times \frac{5}{6}=\frac{25}{18}$
Hence, $t_1:t_2=25:18$.