The ratio of length of two trains is $5:3$ and the ratio of their speed is $6:5$. The ratio of time taken by them to cross a pole is

A

$5:6$

B

$11:8$

C

$25:18$

D

$27:16$

Medium

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Solution

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Correct option is C)

It is given that, $l_{2}l_{1}β=35β$ and $s_{2}s_{1}β=56ββt_{2}t_{1}β=s_{2}l_{2}βs_{1}l_{1}ββ=l_{2}l_{1}βΓs_{1}s_{2}β=35βΓ65β=1825β$ Hence, $t_{1}:t_{2}=25:18$.