The ratio of lone pairs and the number of S-S bonds in S-8 molecules is-

Question

Toppr Admin · Accepted Answer

-S-8- molecule has the following structure- Each sulphur atom is in -sp-3- hybridized state-Number of lone pairs-160- -2-times8-16-160-Number of -S-8722-S- bonds -8-Ratio -dfrac-16-8-2-

The ratio of lone pairs and the number of $$S-S$$ bonds in $$S_8$$ molecules is:

$$S_8$$ molecule has the following structure. Each sulphur atom is in $$sp^3$$ hybridized state.

Number of lone pairs $$=2\times8=16$$

Number of $$S−S$$ bonds $$=8$$

Ratio $$=\dfrac{16}{8}=2$$

The ratio of lone pairs and the number of $$S-S$$ bonds in $$S_8$$ molecules is:

$$S_8$$ molecule has the following structure. Each sulphur atom is in $$sp^3$$ hybridized state.Number of lone pairs $$=2\times8=16$$ Number of $$S−S$$ bonds $$=8$$Ratio $$=\dfrac{16}{8}=2$$

$$S_8$$ molecule has the following structure. Each sulphur atom is in $$sp^3$$ hybridized state.

Number of lone pairs $$=2\times8=16$$

Number of $$S−S$$ bonds $$=8$$

Ratio $$=\dfrac{16}{8}=2$$