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No. of girls$=5x$

$7x+5x=144012x=1440⇒x=120$

$∴$ No. of boys$=120×7=840$

No. of girls$=5×120=600$

Let $y$ be the no. of girls to be added

$⇒34 =600+y840+40 ⇒2400+4y=3320+120⇒4y=3440−2400=1040⇒y=41040 =260$

$∴$ no. of girls that needs to be added $=260$

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