0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

The ratio of number of oxygen atoms(0) In 16,0 g orone (0), 28.0 g carbon monoxide (CO) and 16.09 oxygen (O2) is - (Atomic mass: C-12, 0-16 and Avogadro's constant NX-6_0x10mor") 3:1:2 19 1:1:2

Solution
Verified by Toppr


Was this answer helpful?
0
Similar Questions
Q1
The ratio of number of oxygen atoms (O) in 16.0 g of ozone (O3), 28.0 g carbon monoxide (CO), and 32.0 g oxygen (O2) is:​
View Solution
Q2
The ratio of number of oxygen atoms (O) in 16.0g of ozone (O3), 28.0g carbon monoxide (CO) and 32.0g oxygen (O2) is:
View Solution
Q3
The distance between the carbon atom and the oxygen atom in a carbon monoxide molecule is 1.1 oA. Given, mass of carbon atom is 12 a.m.u. and mass of oxygen atom is 16 a.m.u., calculate the position of the centre of mass of the carbon monoxide molecule
View Solution
Q4
One GAM substance contains Avogadro number of particles in it.
Write the number of atoms present in each of the following.
$$32g$$ Oxygen
(Atomic mass $$S=32, O=16, C=12$$)
View Solution
Q5

calculate the ratio of molcules present in 16g of methane (CH4)and 16g of oxygen (O2). ( atomic masses: C = 12, H = 1, O = 16)

View Solution