Question

The ratio of present ages of Father & son is $8:3$. After $10$ years the ratio of their ages is $2:1$. Then find the present ages of Father.

Answer 1

We have,

Let, percentage, $8x,3x$

Then, after $10$ year;

$\frac{8x+10}{3x+10}=\frac{2}{1}$

$8x+10=6x+20$

$8x-6x=20+10$

$2x=10$

$x=\frac{10}{2}$

$x=5$

$\therefore$ Present age of father,

$=8x$

$=8\times 5$

$=40$ years

Hence, this is answer.