The ratio of the bases radii of two right cones is $2 : 3$ and the ratio of their height is $3 : 2$ , then the ratio of their volumes is:
$1 : 3$
$3 : 2$
$\sqrt{2} : \sqrt{3}$
$2 : 3$

Question

The ratio of the bases radii of two right cones is 2 - 3 and the ratio of their height is 3 - 2- then the ratio of their volumes is-1 - 33 - 2displaystyle sqrt-2-sqrt-3-2 - 3

Toppr Admin · Accepted Answer

We know- volume of a cone -13-x3C0-r2h -where r is the radius of the base of the cone and h is the-height-

The ratio of the bases radii of two right cones is 2:3 and the ratio of their height is 3:2, then the ratio of their volumes is:1:33:2√2:√32:3

We know, volume of a cone =13πr2h ,where r is the radius of the base of the cone and h is the height.

The ratio of the bases radii of two right cones is $2 : 3$ and the ratio of their height is $3 : 2$ , then the ratio of their volumes is:
$1 : 3$
$3 : 2$
$\sqrt{2} : \sqrt{3}$
$2 : 3$

We know, volume of a cone $= \frac{1}{3} π r^{2} h$ ,where $r$ is the radius of the base of the cone and $h$ is the height.