The ratio of the maximum velocity and maximum displacement of a particle executing SHM is equal to
g
n
T
$ω$

Question

The ratio of the maximum velocity and maximum displacement of a particle executing SHM is equal tognTomega

Toppr Admin · Accepted Answer

X-Asin-x3C9-t-x3B8- thus maximum x occurs at maximum value of sine- i-e- 1- which is x-Av-dx-dt-A-x3C9-cos-x3C9-t-x3B8- thus-xA0-maximum v occurs at maximum value of cosine- i-e- 1- which is v-A-x3C9-Thus- ratio is A-x3C9-A-x3C9-

The ratio of the maximum velocity and maximum displacement of a particle executing SHM is equal tognTω

x=Asin(ωt+θ), thus maximum x occurs at maximum value of sine, i.e. 1, which is x=Av=dx/dt=Aωcos(ωt+θ), thus maximum v occurs at maximum value of cosine, i.e. 1, which is v=AωThus, ratio is Aω/A=ω

The ratio of the maximum velocity and maximum displacement of a particle executing SHM is equal to
g
n
T
$ω$

$x = A s i n (ω t + θ)$ , thus maximum x occurs at maximum value of sine, i.e. 1, which is x=A
$v = d x / d t = A ω c o s (ω t + θ)$ , thus maximum v occurs at maximum value of cosine, i.e. 1, which is $v = A ω$
Thus, ratio is $A ω / A = ω$