The ratio of work done by an ideal monoatomic gas to the heat supplied to it in an isobaric process is:
$\frac{2}{3}$
$\frac{3}{2}$
$\frac{3}{5}$
$\frac{2}{5}$

Question

The ratio of work done by an ideal monoatomic gas to the heat supplied to it in an isobaric process is-dfrac-2-3-dfrac-3-2-dfrac-3-5-dfrac-2-5-

Toppr Admin · Accepted Answer

In isobaric process- heat supplied is Q-nCP-x394-T-Work done is W-P-x394-V-nR-x394-T-Hence ratio is RCP-R-x3B3-R-x3B3-x2212-1-25 -xA0-x2235-x3B3-53- for a monoatomic gas-xA0-

The ratio of work done by an ideal monoatomic gas to the heat supplied to it in an isobaric process is:23323525

In isobaric process, heat supplied is Q=nCPΔT.Work done is W=PΔV=nRΔT.Hence ratio is RCP=RγRγ−1=25 [∵γ=53, for a monoatomic gas]

The ratio of work done by an ideal monoatomic gas to the heat supplied to it in an isobaric process is:
$\frac{2}{3}$
$\frac{3}{2}$
$\frac{3}{5}$
$\frac{2}{5}$

In isobaric process, heat supplied is $Q = n C_{P} Δ T$ .

Work done is $W = P Δ V = n R Δ T$ .

Hence ratio is $\frac{R}{C_{P}} = \frac{R}{\frac{γ R}{γ - 1}} = \frac{2}{5}$ [ $∵ γ = \frac{5}{3}$ , for a monoatomic gas]