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Question

The ratio of work function and temperature of two emitters are 1 : 2, then the ratio of current densities obtained by them will be


  1. 4:1
  2. 2:1
  3. 1:4
  4. 1:2

A
1:4
B
4:1
C
1:2
D
2:1
Solution
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J1J2=AT21eW1/kT1AT22eW2/kT2

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