The reaction, A+2B⇌2C+D was studied using an initial concentration of B which was 1.5 times that of A. But the equilibrium concentration of A and C were found to be equal. Then the Kc for the equilibrium is :
0. 41
0. 83
0. 66
0. 32
A
0. 66
B
0. 32
C
0. 41
D
0. 83
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Solution
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A+2B⇌2C+D
At t=0α32α00
At eq. α−x32α−x2xx
Given, [A]=[C]
a−x=2x
∴x=a3
Now, Kc=[C]2[D][A][B]2
=(2a3)2×a3(a−a3)(3a2−2a3)2=0.32
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