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Reaction of Acids with Metals

Question

The reaction of aluminum atoms displacing hydrogen ions from sulphuric acid can be represented as:
$2 A l + 3 H_{2} S O_{4} \to A l_{2} (S O_{4})_{3} + 3 H_{2}$
$3 A l + 2 H_{2} S O_{4} \to A l_{3} (S O_{4})_{2} + 2 H_{2}$
$A l + 3 H_{2} S O_{4} \to A l_{2} (S O_{4})_{3} + H_{2}$
$2 A l + 6 H_{2} S O_{4} \to A l_{2} (S O_{4})_{6} + 6 H_{2}$

A

2 A l + 3 H_{2} S O_{4} \to A l_{2} (S O_{4})_{3} + 3 H_{2}

B

3 A l + 2 H_{2} S O_{4} \to A l_{3} (S O_{4})_{2} + 2 H_{2}

C

2 A l + 6 H_{2} S O_{4} \to A l_{2} (S O_{4})_{6} + 6 H_{2}

D

A l + 3 H_{2} S O_{4} \to A l_{2} (S O_{4})_{3} + H_{2}

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Solution

Verified by Toppr

The reaction of aluminium atoms displacing hydrogen ions from sulphuric acid can be represented as :
$2 A l + 3 H_{2} S O_{4} \to A l_{2} (S O_{4})_{3} + 3 H_{2}$
This is the balanced chemical equation.
The products of the reaction are aluminium sulphate and hydrogen.

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