The reciprocal of dfrac-3-8- times left-dfrac-7-13-right- is

Question

Toppr Admin · Accepted Answer

Correct option is A- -dfrac-104-21-We have -dfrac-3-8- -times -left-dfrac-7-13-right-dfrac-3-times 7-8-times 13-dfrac -21-104-Let -x- be its reciprocal-Then -x-times-dfrac-21-104-1- -Rightarrow x-dfrac -104-21-Hence- option A is the correct answer-

The reciprocal of $$\dfrac{-3}{8} \times \left(\dfrac{-7}{13}\right)$$ is

Correct option is A. $$\dfrac{104}{21}$$
We have $$\dfrac{-3}{8} \times \left(\dfrac{-7}{13}\right)=\dfrac{3\times 7}{8\times 13}=\dfrac {21}{104}$$

Let $$x$$ be its reciprocal.
Then $$x\times\dfrac{21}{104}=1$$
$$ \Rightarrow x=\dfrac {104}{21}$$

Hence, option A is the correct answer.

The reciprocal of $$\dfrac{-3}{8} \times \left(\dfrac{-7}{13}\right)$$ is

Correct option is A. $$\dfrac{104}{21}$$We have $$\dfrac{-3}{8} \times \left(\dfrac{-7}{13}\right)=\dfrac{3\times 7}{8\times 13}=\dfrac {21}{104}$$Let $$x$$ be its reciprocal.Then $$x\times\dfrac{21}{104}=1$$$$ \Rightarrow x=\dfrac {104}{21}$$Hence, option A is the correct answer.

Correct option is A. $$\dfrac{104}{21}$$
We have $$\dfrac{-3}{8} \times \left(\dfrac{-7}{13}\right)=\dfrac{3\times 7}{8\times 13}=\dfrac {21}{104}$$

Let $$x$$ be its reciprocal.
Then $$x\times\dfrac{21}{104}=1$$
$$ \Rightarrow x=\dfrac {104}{21}$$

Hence, option A is the correct answer.