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# The refracting angle of a prism is A and the refractive index of the material of the prism is cotA2. The angle of minimum deviation of the prism isπ+2Aπ−2Aπ2−Aπ2+A

A
π+2A
B
π2A
C
π2+A
D
π2A
Solution
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#### It is given μ=cotA/2We know that:μ=sin(δm+A2)sinA/2⇒cotA/2=sin(δm+A2)sin(A/2)⇒cosA/2sinA/2=sin(δm+A2)sinA/2⇒sin(π/2−A/2)=sin(δm+A2)⇒π/2−A/2=δm+A2⇒π−2A=δm

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