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Question

- π+2A
- π−2A
- π2−A
- π2+A

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Solution

Verified by Toppr

We know that:

μ=sin(δm+A2)sinA/2

⇒cotA/2=sin(δm+A2)sin(A/2)

⇒cosA/2sinA/2=sin(δm+A2)sinA/2

⇒sin(π/2−A/2)=sin(δm+A2)

⇒π/2−A/2=δm+A2

⇒π−2A=δm

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