The refractive index of diamond is $6$ an that of a liquid is $3$ . If light travels from diamond to the liquid, it will be totally reflected when the angle of incidence is $3 0^{\circ}$

Question

Verified by Toppr

Answer 1

$6 S i n θ = 3 S i n 90$

$⟶ θ = 4 5^{o}$

So the angle of incidence has to be more than $4 5^{\circ}$ for total internal reflection
The assertion is wrong. The reason is correct

Answer 2

6 S i n θ = 3 S i n 90

⟶ θ = 4 5^{o}

So the angle of incidence has to be more than

4 5^{\circ}

for total internal reflection

The assertion is wrong. The reason is correct

The refractive index of diamond is $6$ an that of a liquid is $3$ . If light travels from diamond to the liquid, it will be totally reflected when the angle of incidence is $3 0^{\circ}$

$μ = \frac{1}{sin c}$ , where $μ$ is the refractive index of diamond w.r.t liquid

Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

Assertion is correct but Reason is incorrect

Assertion is incorrect but Reason are correct

$6 S i n θ = 3 S i n 90$

$⟶ θ = 4 5^{o}$

So the angle of incidence has to be more than $4 5^{\circ}$ for total internal reflection
The assertion is wrong. The reason is correct

The maximum refractive index of liquid for total internal reflection of the ray passing through the prism should be $2$

Here critical angle is $4 5^{\circ}$

The index of refraction for diamond is $2.42$ . For a diamond in the air (index of refraction $= 1.00$ ), what is the smallest angle that a light ray inside the diamond can make with a normal and completely reflect back inside the diamond (the critical angle)?

The index of refraction for diamond is $2.42$ . For a diamond in the air (index of refraction = $1.00$ ), what is the smallest angle that a light ray inside the diamond can make with a normal and completely reflect back inside the diamond (the critical angle)?

A vertical pencil of rays comes from bottom of a tank filled with a liquid. When it is accelerated with an acceleration of 7.5 m/s $^{2}$ , the ray is seen to be totally reflected by liquid surface. What is minimum possible refractive index of liquid?

Revise with Concepts

Total Internal Reflection and Critical angle

Optical Fibres

Critical Angle - Formula

Applications of Total Internal Reflection

Prism binoculars

The refractive index of diamond is 6​ an that of a liquid is 3​. If light travels from diamond to the liquid, it will be totally reflected when the angle of incidence is 30∘

μ=sinc1​, where μ is the refractive index of diamond w.r.t liquid

Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

Assertion is correct but Reason is incorrect

Assertion is incorrect but Reason are correct

6​Sinθ=3​Sin90 ⟶θ=45o So the angle of incidence has to be more than 45∘ for total internal reflectionThe assertion is wrong. The reason is correct

The maximum refractive index of liquid for total internal reflection of the ray passing through the prism should be 2​

Here critical angle is 45∘

The index of refraction for diamond is 2.42. For a diamond in the air (index of refraction =1.00), what is the smallest angle that a light ray inside the diamond can make with a normal and completely reflect back inside the diamond (the critical angle)?

The index of refraction for diamond is 2.42. For a diamond in the air (index of refraction = 1.00), what is the smallest angle that a light ray inside the diamond can make with a normal and completely reflect back inside the diamond (the critical angle)?

A vertical pencil of rays comes from bottom of a tank filled with a liquid. When it is accelerated with an acceleration of 7.5 m/s2, the ray is seen to be totally reflected by liquid surface. What is minimum possible refractive index of liquid?

Revise with Concepts

Total Internal Reflection and Critical angle

Optical Fibres

Critical Angle - Formula

Applications of Total Internal Reflection

Prism binoculars

The refractive index of diamond is $6$ an that of a liquid is $3$ . If light travels from diamond to the liquid, it will be totally reflected when the angle of incidence is $3 0^{\circ}$

$μ = \frac{1}{sin c}$ , where $μ$ is the refractive index of diamond w.r.t liquid

$6 S i n θ = 3 S i n 90$

$⟶ θ = 4 5^{o}$

So the angle of incidence has to be more than $4 5^{\circ}$ for total internal reflection
The assertion is wrong. The reason is correct

The maximum refractive index of liquid for total internal reflection of the ray passing through the prism should be $2$

Here critical angle is $4 5^{\circ}$

The index of refraction for diamond is $2.42$ . For a diamond in the air (index of refraction $= 1.00$ ), what is the smallest angle that a light ray inside the diamond can make with a normal and completely reflect back inside the diamond (the critical angle)?

The index of refraction for diamond is $2.42$ . For a diamond in the air (index of refraction = $1.00$ ), what is the smallest angle that a light ray inside the diamond can make with a normal and completely reflect back inside the diamond (the critical angle)?

A vertical pencil of rays comes from bottom of a tank filled with a liquid. When it is accelerated with an acceleration of 7.5 m/s $^{2}$ , the ray is seen to be totally reflected by liquid surface. What is minimum possible refractive index of liquid?