The refractive index of glass is 1-520 red light and 1-525 blue light- Let D-1- and D-2- be an of minimum deviation red and blue light respectively in a prism of this glass- Then mathrm-D-1-mathrm-D-2-mathrm-D-1-mathrm-D-2-mathrm-D-1-D-2-mathrm-D-1- can be than or greater than depending upon the angle of prism-

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A prism follows -x3BC-sin-A-D2-sin-A2-where A is the angle of prism-Clearly- greater the refractive index -x3BC- greater the angle of deviation D-Hence -x3BC-blue-gt-x3BC-red-x27F9-D2-gt-D1

The refractive index of glass is 1.520 for red light and 1.525 for blue light. Let D1 and D2 be an of minimum deviation for red and blue light respectively in a prism of this glass. Then D1>D2D1<D2D1=D2D1 can be less than or greater than depending upon the angle of prism.

A prism follows μ=sin(A+D2)sin(A2)where A is the angle of prism.Clearly, greater the refractive index μ, greater the angle of deviation D.Hence μblue>μred⟹D2>D1

A prism follows $μ = \frac{s i n (\frac{A + D}{2})}{s i n (\frac{A}{2})}$

where $A$ is the angle of prism.

Clearly, greater the refractive index $μ$ , greater the angle of deviation $D$ .

Hence $μ_{b l u e} > μ_{r e d}$

$⟹ D_{2} > D_{1}$