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Correct option is B)

Focal length of a lens is given by:-

$f1 =(n−1)(R_{1}1 −R_{2}1 )$ where $n=μ_{_{′}}μ $

Since, here, $n=μ_{_{′}}μ >1$ and by convention $R_{1}$ is negative and $R_{2}$ is positive

Hence, $f$ comes out to be negative.

Thus, this system will behave as a $Concave$ $lens$ though with larger focal length than in air.

Hence,option-(B) is correct.

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