The refractive index of the material of a concave lens is $μ .$ It is immersed in a medium of refractive index $μ_{1}$ . A parallel beam of light is incident on the lens. The path of the emergent rays when $μ_{1} > μ$ is :

Question

The refractive index of the material of a concave lens is $μ .$ It is immersed in a medium of refractive index $μ_{1}$ . A parallel beam of light is incident on the lens. The path of the emergent rays when $μ_{1} > μ$ is :

Toppr Admin · Accepted Answer

From the laws of optics- we know that a lens reverses its behaviour when placed in a medium of higher refractive index- Hence- a concave lens diverges light in general- but when placed in a medium of higher refractive index it converges parallel rays of light to a focal point-

The refractive index of the material of a concave lens is μ. It is immersed in a medium of refractive index μ1. A parallel beam of light is incident on the lens. The path of the emergent rays when μ1>μ is :

From the laws of optics, we know that a lens reverses its behaviour when placed in a medium of higher refractive index. Hence, a concave lens diverges light in general, but when placed in a medium of higher refractive index it converges parallel rays of light to a focal point.

The refractive index of the material of a concave lens is $μ .$ It is immersed in a medium of refractive index $μ_{1}$ . A parallel beam of light is incident on the lens. The path of the emergent rays when $μ_{1} > μ$ is :