The relation between T and g by

Question

Toppr Admin · Accepted Answer

T - time period of oscillation-xA0-g - effective acceleration on pendulum-xA0-l - length of pendulum-so- T-2-x3C0-x221A-lg-x21D2-T2-4-x3C0-2lg-x21D2-T2-x221D-1gWhen l is unchanged-

The relation between T and g by

T = time period of oscillation g = effective acceleration on pendulum l = length of pendulum.so, T=2π√lg⇒T2=4π2lg⇒T2∝1gWhen l is unchanged.

T = time period of oscillation
g = effective acceleration on pendulum
l = length of pendulum.
so, $T = 2 π \sqrt{\frac{l}{g}} \Rightarrow T^{2} = 4 π^{2} \frac{l}{g} \Rightarrow T^{2} \propto \frac{1}{g}$
When $l$ is unchanged.