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Question

# The relation between time t and distance x is t=ax2+bx where a and b are constants.The acceleration is−2av32av2−2av22bv3

A
2av2
B
2av2
C
2bv3
D
2av3
Solution
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#### The correct option is A−2av3t=ax2+bxDifferentiate w.r.t time1=2axdxdt+bdxdtdxdt=12ax+bV=12ax+b...(1)a=dVdt=−(2adxdt)(2ax+b)2a=−2av(2ax+b)2....(2)Substiting 12ax+b=V in (2)we will get, a=−2av3

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