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Question

The relation between time t and distance x is t=ax2+bx where a and b are constants.The acceleration is
  1. 2av3
  2. 2av2
  3. 2av2
  4. 2bv3

A
2av2
B
2av2
C
2bv3
D
2av3
Solution
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The correct option is A 2av3
t=ax2+bx
Differentiate w.r.t time
1=2axdxdt+bdxdt
dxdt=12ax+b
V=12ax+b...(1)
a=dVdt=(2adxdt)(2ax+b)2
a=2av(2ax+b)2....(2)
Substiting 12ax+b=V in (2)
we will get, a=2av3

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