The resistance of a bulb filament is 100 $Ω$ at a temperature of 100 $^{0}$ C. If its temperature coefficient of resistance be 0.005 per $^{0}$ C , its resistance will become 200 $Ω$ at a temperature of :

Question

The resistance of a bulb filament is 100

Ω

at a temperature of 100

^{0}

C. If its temperature coefficient of resistance be 0.005 per

^{0}

C , its resistance will become 200

Ω

at a temperature of :

Toppr Admin · Accepted Answer

Given R0-100-xA0-x3A9-xA0-at-xA0-1000c- -x3B1-0-005-R-200-xA0-x3A9-xA0-at-xA0-T- -x21D2-R-x2212-R0-R0-x3B1-T-x2212-T0- -x21D2-100-100-xD7-51000-T-x2212-T0- -x21D2-T-200-T0-3000c

The resistance of a bulb filament is 100 $Ω$ at a temperature of 100 $^{0}$ C. If its temperature coefficient of resistance be 0.005 per $^{0}$ C , its resistance will become 200 $Ω$ at a temperature of :
300 $^{0}$ C
400 $^{0}$ C
500 $^{0}$ C
200 $^{0}$ C

Given $R_{0} = 100 Ω a t 100^{0} c .$
$α = 0.005; R = 200 Ω a t T = ?$
$\Rightarrow (R - R_{0}) = R_{0} α (T - T_{0})$
$\Rightarrow 100 = 100 \times \frac{5}{1000} (T - T_{0})$
$\Rightarrow T = 200 + T_{0} = 300^{0} c$

The resistance of a bulb filament is 100Ω at a temperature of 1000C. If its temperature coefficient of resistance be 0.005 per 0C , its resistance will become 200Ω at a temperature of :3000C4000C5000C2000C

Given R0=100 Ω at 1000c. α=0.005;R=200 Ω at T=? ⇒(R−R0)=R0α(T−T0) ⇒100=100×51000(T−T0) ⇒T=200+T0=3000c

The resistance of a bulb filament is 100 $Ω$ at a temperature of 100 $^{0}$ C. If its temperature coefficient of resistance be 0.005 per $^{0}$ C , its resistance will become 200 $Ω$ at a temperature of :
300 $^{0}$ C
400 $^{0}$ C
500 $^{0}$ C
200 $^{0}$ C

Given $R_{0} = 100 Ω a t 100^{0} c .$
$α = 0.005; R = 200 Ω a t T = ?$
$\Rightarrow (R - R_{0}) = R_{0} α (T - T_{0})$
$\Rightarrow 100 = 100 \times \frac{5}{1000} (T - T_{0})$
$\Rightarrow T = 200 + T_{0} = 300^{0} c$