The resistance of a wire is 5 ohm at 50∘C and 6 ohm at 100∘C. The resistance of the wire at 0∘C will be:
2 ohm
1 ohm
4 ohm
3 ohm
A
2 ohm
B
1 ohm
C
3 ohm
D
4 ohm
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Solution
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R=R0(1+αΔT)
R at 1000C=6Ω
R at 500c=5Ω
⇒5(1+α(50))=6(1+α(100))
⇒6(1+α(50))=5(1+α(100))
⇒α=1200
R=R0(1+αΔT)
R at 500C=5Ω
R0 at 00C=R0
⇒R=R0(1+1200×50)
⇒5=R0(1+1200×50)
⇒R0=4Ω
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