The resistivity of a conductor with a current density of 2.5Am−2 when an electric field 5×10−8Vm−1 is applied to it, is
1.0×10−8Ωm
2.0×10−8Ωm
0.5×10−8Ωm
12.5×10−8Ωm
A
2.0×10−8Ωm
B
0.5×10−8Ωm
C
12.5×10−8Ωm
D
1.0×10−8Ωm
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Solution
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The correct option is B2.0×10−8Ωm
Step 1:Relation between Electric field(E), Resistivity and Current density(J)
Suppose length of conductor =l
We know that, Potential difference, V=E.l
& Current Density J=I/A So, I=JA
and R=ρlA
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