The resultant amplitude due to superposition of two waves
$y_{1} = 5 sin (w t - k x)$ and
$y_{2} = - 5 cos (w t - k x - 30^{\circ}$ )

Question

The resultant amplitude due to superposition of two SHMs-  x-1- -10 sin-omega t-30-circ- -cm and  x-2- - 10 cos - omega t-60-circ- -cm is5 cm10 cm20 cmzero

Toppr Admin · Accepted Answer

X1-10sin-wt-300-x2-10cos-wt-600-x2212-sin-wt-x2212-30-sin-wt-150-

The resultant amplitude due to superposition of two SHMs, $x_{1} = 10 s i n (ω t + 30^{\circ}$ )cm and $x_{2}$ = 10 cos ( $ω t + 60^{\circ}$ )cm is
$5 c m$
$10 c m$
$20 c m$
$z e r o$

$x_{1} = 10 s i n (w t + 30^{0})$
$x_{2} = 10 c o s (w t + 60^{0}) = - s i n (w t - 30) = s i n (w t + 150)$

The resultant amplitude due to superposition of two SHMs, x1=10sin(ωt+30∘)cm and x2= 10 cos (ωt+60∘)cm is5cm10cm20cmzero

x1=10sin(wt+300)x2=10cos(wt+600)=−sin(wt−30)=sin(wt+150)

The resultant amplitude due to superposition of two SHMs, $x_{1} = 10 s i n (ω t + 30^{\circ}$ )cm and $x_{2}$ = 10 cos ( $ω t + 60^{\circ}$ )cm is
$5 c m$
$10 c m$
$20 c m$
$z e r o$

$x_{1} = 10 s i n (w t + 30^{0})$
$x_{2} = 10 c o s (w t + 60^{0}) = - s i n (w t - 30) = s i n (w t + 150)$