The r.m.s value of an alternating current of 50Hz is 10A. The time taken by the alternating current in reaching from zero to maximum value and the peak value of current will be :
2×10−2sec and 14.14amp
1×10−2sec and 7.07amp
5×10−3sec and 7.07amp
5×10−3sec and 14.14amp
A
2×10−2sec and 14.14amp
B
1×10−2sec and 7.07amp
C
5×10−3sec and 14.14amp
D
5×10−3sec and 7.07amp
Open in App
Solution
Verified by Toppr
Irms=I0√2
⇒I0=Irms√2
=10×√2
Was this answer helpful?
0
Similar Questions
Q1
The r.m.s value of an alternating current of 50Hz is 10A. The time taken by the alternating current in reaching from zero to maximum value and the peak value of current will be :
View Solution
Q2
The r.m.s. value of an ac of 50 Hz is 10 amp. The time taken by the alternating current in reaching from zero to maximum value and the peak value of current will be
View Solution
Q3
The root-mean-square value of an alternating current of 50Hz frequency is 10 ampere. The time taken by the alternating current in reaching from zero to maximum value and the peak value of current will be:
View Solution
Q4
The r.m.s value of an a.c of 50Hz is 10amp. The time taken by the alternating current in reaching from zero to maximum value and the peak value of current will be:
View Solution
Q5
The r.m.s. value of an ac of 50 Hz is 10 amp. The time taken by the alternating current in reaching from zero to maximum value and the peak value of current will be