The sequence of bands in carbon resistor are brown, black, brown and gold, the value of resistance is (in $Ω$ )
Exactly 100
95 to 105
90 to 110
80 to 120

Question

The sequence of bands in carbon resistor are brown- black- brown and gold- the value of resistance is -in Omega-Exactly 10095 to 10590 to 11080 to 120

Toppr Admin · Accepted Answer

1stBand-Brown-x2212-12ndBand-Black-x2212-0Multiplier-Brown-x2212-xD7-10-x3A9-Tolerance-xB1-5-Resistorvalue-100-x3A9-xB1-5-95 to 105-x3A9-xA0-

The sequence of bands in carbon resistor are brown, black, brown and gold, the value of resistance is (in Ω)Exactly 10095 to 10590 to 11080 to 120

1stBand:Brown−12ndBand:Black−0Multiplier:Brown−×10ΩTolerance:±5%Resistorvalue:100Ω±5%95 to 105Ω

The sequence of bands in carbon resistor are brown, black, brown and gold, the value of resistance is (in $Ω$ )
Exactly 100
95 to 105
90 to 110
80 to 120

$1^{s t} B a n d : B r o w n - 1$
$2^{n d} B a n d : B l a c k - 0$
$M u l t i p l i e r : B r o w n - \times 10 Ω$
$T o l e r a n c e : \pm 5 %$
$R e s i s t o r v a l u e : 100 Ω \pm 5 %$
$95$ to $105 Ω$