The shadow cast by a tower is 30 m long when the elevation of is displaystyle 30-circ- If the elevation of is displaystyle 60-circ- then the length of the shadow is 30 m20 m10 mdisplaystyle 10sqrt-3- m

Question

The shadow cast by a tower is 30 m long when the elevation of is displaystyle 30-circ-  If the elevation of is displaystyle 60-circ-  then the length of the shadow is 30 m20 m10 mdisplaystyle 10sqrt-3- m

Toppr Admin · Accepted Answer

The correct option is C 10 mtan30-x2218-h30 or-xA0-1-x221A-3-h30-x2234-h-30-x221A-3tan60-x2218-30-x221A-3xor-xA0-x221A-3-30x-x221A-3-x2234- x-10

the shadow cast by a tower is 30 m long when the elevation of sum is $30^{\circ}$ If the elevation of sum is $60^{\circ}$ then the length of the shadow is
30 m
20 m
10 m
$10 \sqrt{3} m$

The correct option is C 10 m
$tan 30^{\circ} = \frac{h}{30}$ or $\frac{1}{\sqrt{3}} = \frac{h}{30}$
$∴ h = \frac{30}{\sqrt{3}}$
$tan 60^{\circ} = \frac{30 / \sqrt{3}}{x}$
or $\sqrt{3} = \frac{30}{x \sqrt{3}}$
$∴$ x=10

the shadow cast by a tower is 30 m long when the elevation of sum is 30∘ If the elevation of sum is 60∘ then the length of the shadow is 30 m20 m10 m10√3m

The correct option is C 10 mtan30∘=h30 or 1√3=h30∴h=30√3tan60∘=30/√3xor √3=30x√3∴ x=10

the shadow cast by a tower is 30 m long when the elevation of sum is $30^{\circ}$ If the elevation of sum is $60^{\circ}$ then the length of the shadow is
30 m
20 m
10 m
$10 \sqrt{3} m$

The correct option is C 10 m
$tan 30^{\circ} = \frac{h}{30}$ or $\frac{1}{\sqrt{3}} = \frac{h}{30}$
$∴ h = \frac{30}{\sqrt{3}}$
$tan 60^{\circ} = \frac{30 / \sqrt{3}}{x}$
or $\sqrt{3} = \frac{30}{x \sqrt{3}}$
$∴$ x=10