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Dimensional Analysis

Question

The SI unit of a physical quantity is [ $J m^{- 2}$ ]. The dimensional formula for that quantity is:
$M^{1} L^{2} T^{- 1}$
$M^{1} L^{0} T^{- 2}$
$M^{1} L^{- 2}$
$M^{1} L^{- 1} T^{- 2}$

A

M^{1} L^{- 2}

B

M^{1} L^{0} T^{- 2}

C

M^{1} L^{2} T^{- 1}

D

M^{1} L^{- 1} T^{- 2}

Open in App

Solution

Verified by Toppr

$[J m^{- 2}] = [\frac{M^{1} L^{2} T^{- 2}}{L^{2}}] = [M^{1} L^{0} T^{- 2}]$

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The SI unit of a physical quantity is [

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