Question

The smallest number which when divided by 4, 6, 10, 15 gives the same remainder 3 is

• A. 57
• B. 123
• C. 39
• D. 63

Answer 1

Answer: (D)

The correct option is C 63
$\therefore$ LCM of 4, 6, 10, 15
= $2\times 5\times 3\times 2\times 1\times 1\times 1=60$
$\therefore$ Required number $=60+3=63$