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Question

The solubility of AgCl(s) with solubility product 1.6×1010 in 0.1 M NaCl solution would be :
  1. 1.6×1011M
  2. 1.26×105M
  3. 1.6×109M
  4. zero

A
1.26×105M
B
zero
C
1.6×109M
D
1.6×1011M
Solution
Verified by Toppr

AgClAg++Cl
a 0 0
a-S S S+0.1
ksp=1.6×1010=[Ag+][Cl]

=S(0.1+S)

ksp is value seems to be very small

S value can be ignored, with respect to 0.1 M

1.6×1010=S×0.1

S=1.6×109M

Hence option D is correct.

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