The solubility product of NaCl is 2-5 times 10-9- moles-2-lit-2- Its solubility is-2-5 times 10-9- mol-lit5 times 10-5- moles-2-lit-2-5 times 10-5- mol-lit1-3 times 10-5- mol-lit

Question

The solubility product of NaCl is 2-5 times 10-9-  moles-2-lit-2- Its solubility is-2-5 times 10-9- mol-lit5 times 10-5-  moles-2-lit-2-5 times 10-5- mol-lit1-3 times 10-5- mol-lit

Toppr Admin · Accepted Answer

Ksp-s2-gt-s-x221A-Ksp-5-x2217-10-x2212-5-xA0-

The solubility product of NaCl is $2.5 \times 10^{- 9}$ $m o l e s^{2} / l i t^{2}$ . Its solubility is:
$2.5 \times 10^{- 9} m o l / l i t$
$5 \times 10^{- 5}$ $m o l e s^{2} / l i t^{2}$
$5 \times 10^{- 5} m o l / l i t$
$1.3 \times 10^{- 5} m o l / l i t$

$K_{s p} = s^{2}$
=> $s = \sqrt{K_{s p}} = 5 * 10^{- 5}$

The solubility product of NaCl is 2.5×10−9 moles2/lit2. Its solubility is:2.5×10−9mol/lit5×10−5 moles2/lit25×10−5mol/lit1.3×10−5mol/lit

Ksp=s2=>s=√Ksp=5∗10−5

The solubility product of NaCl is $2.5 \times 10^{- 9}$ $m o l e s^{2} / l i t^{2}$ . Its solubility is:
$2.5 \times 10^{- 9} m o l / l i t$
$5 \times 10^{- 5}$ $m o l e s^{2} / l i t^{2}$
$5 \times 10^{- 5} m o l / l i t$
$1.3 \times 10^{- 5} m o l / l i t$

$K_{s p} = s^{2}$
=> $s = \sqrt{K_{s p}} = 5 * 10^{- 5}$