-The species -CuCl-4-2- exists- while -CuI-4-2- does not-If true enter 1-if false enter 0-1

Question

Toppr Admin · Accepted Answer

-quot-The specics -CuCl4-2-x2212- exists- while -CuI4-2-x2212- does-xA0-not-quot-2CuI2-x2192-Cu2I2-I2Iodide ion reduces Cu2- to cuprous iodide and I2- So -CuI4-2-x2212- does not exist-

"The species [CuCl $_{4}$ ] $^{2 -}$ exists, while [CuI $_{4}$ ] $^{2 -}$ does not"
If true enter 1,if false enter 0.

1

"The specics $[C u C l_{4}]^{2 -}$ exists, while $[C u I_{4}]^{2 -}$ does not"
$2 C u I_{2} \to C u_{2} I_{2} + I_{2}$
Iodide ion reduces $C u^{2 +}$ to cuprous iodide and $I_{2}$ . So $[C u I_{4}]^{2 -}$ does not exist.

"The species [CuCl4]2− exists, while [CuI4]2− does not"If true enter 1,if false enter 0.1

"The specics [CuCl4]2− exists, while [CuI4]2− does not"2CuI2→Cu2I2+I2Iodide ion reduces Cu2+ to cuprous iodide and I2. So [CuI4]2− does not exist.

"The species [CuCl $_{4}$ ] $^{2 -}$ exists, while [CuI $_{4}$ ] $^{2 -}$ does not"
If true enter 1,if false enter 0.

1

"The specics $[C u C l_{4}]^{2 -}$ exists, while $[C u I_{4}]^{2 -}$ does not"
$2 C u I_{2} \to C u_{2} I_{2} + I_{2}$
Iodide ion reduces $C u^{2 +}$ to cuprous iodide and $I_{2}$ . So $[C u I_{4}]^{2 -}$ does not exist.