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Specific activity of the sample

$$ = \dfrac{1}{M + M'} $$ [ Activity of $$M\,gm$$ of $$Co^{58} $$ in the sample]

Here $$M$$ and $$M'$$ are the masses of $$Co^{58} $$ and $$Co^{59}$$ in the sample. Now activity of $$M\,gm$$ of $$Co^{58} $$

$$ = \dfrac{M}{58} \times 6.023 \times 10^{23} \times \dfrac{ln\ 2}{71.3 \times 86400} $$ dis/sec

$$ = 1.168 \times 10^{15} M $$

Thus from the problem

$$ 1.168 \times 10^{15} \dfrac{M}{M + M'} = 2.2 \times 10^{12} $$

or $$ \dfrac{M}{M + M'} = 1.88 \times 10^{-3} $$ i.e., $$ 0.188\%$$

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