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Question

The standard reduction potential data at $${25}^{o}C$$ is given below:

(i) $${ E }^{ o }\left( { Fe }^{ 3+ },{ Fe }^{ 2+ } \right) =-0.77V$$
(ii) $${ E }^{ o }\left( { Fe }^{ 2+ },{ Fe }^{ } \right) =-0.44V$$
(iii) $${ E }^{ o }\left( { Cu }^{ 2+ },{ Cu }^{ } \right) =+0.34V\quad $$
(iv) $${ E }^{ o }\left( { Cu }^{ + },{ Cu }^{ } \right) =+0.52V$$
(v) $${ E }^{ o }({ O }_{ 2\ (g)}+{ H }^{ + }+4e\rightarrow 4O{ H }^{ - })=+1.23V$$
(vi) $${ E }^{ o }({ O }_{ 2\ (g)}+2{ H }_{ 2 }O+4e\rightarrow 4{ OH }^{ - })=+0.40V$$
(vii) $${ E }^{ o }\left( { Cr }^{ 3+ },{ Cr }^{ } \right) =-0.74V$$
(viii) $${ E }^{ o }\left( { Cr }^{ 2+ },{ Cr }^{ } \right) =+0.91V\quad $$
Match $${E}^{o}$$ of the redox pair in List-I with the values given in List-II and select the correct answer using the code given below the lists

List IList II
(P) $${E}^{o}({ Fe }^{ 3+ },{ Fe })$$(1) $$-0.18V$$
(Q) $${E}^{o}(4{ H }_{ 2 }O\rightleftharpoons 4{ H }^{ + }+4{ OH }^{ - })$$(2) $$-0.4V$$
(R) $${E}^{o}({ Cu }^{ + },{ Cu }\rightarrow 2{Cu}^{+})$$(3) $$-0.04V$$
(S) $${E}^{o}({Cr}^{3+},{Cr}^{2+})$$(4) $$-0.83V$$

A
$$P-3; Q- 4; R-1; S-2$$
B
$$P-1; Q- 2; R-3; S-4$$
C
$$P-4; Q- 1; R-2; S-3$$
D
$$P-2; Q- 3; R-4; S-1$$
Solution
Verified by Toppr

Correct option is D. $$P-3; Q- 4; R-1; S-2$$

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Similar Questions
Q1
The standard reduction potential data at $${25}^{o}C$$ is given below:

(i) $${ E }^{ o }\left( { Fe }^{ 3+ },{ Fe }^{ 2+ } \right) =-0.77V$$
(ii) $${ E }^{ o }\left( { Fe }^{ 2+ },{ Fe }^{ } \right) =-0.44V$$
(iii) $${ E }^{ o }\left( { Cu }^{ 2+ },{ Cu }^{ } \right) =+0.34V\quad $$
(iv) $${ E }^{ o }\left( { Cu }^{ + },{ Cu }^{ } \right) =+0.52V$$
(v) $${ E }^{ o }({ O }_{ 2\ (g)}+{ H }^{ + }+4e\rightarrow 4O{ H }^{ - })=+1.23V$$
(vi) $${ E }^{ o }({ O }_{ 2\ (g)}+2{ H }_{ 2 }O+4e\rightarrow 4{ OH }^{ - })=+0.40V$$
(vii) $${ E }^{ o }\left( { Cr }^{ 3+ },{ Cr }^{ } \right) =-0.74V$$
(viii) $${ E }^{ o }\left( { Cr }^{ 2+ },{ Cr }^{ } \right) =+0.91V\quad $$
Match $${E}^{o}$$ of the redox pair in List-I with the values given in List-II and select the correct answer using the code given below the lists

List IList II
(P) $${E}^{o}({ Fe }^{ 3+ },{ Fe })$$(1) $$-0.18V$$
(Q) $${E}^{o}(4{ H }_{ 2 }O\rightleftharpoons 4{ H }^{ + }+4{ OH }^{ - })$$(2) $$-0.4V$$
(R) $${E}^{o}({ Cu }^{ + },{ Cu }\rightarrow 2{Cu}^{+})$$(3) $$-0.04V$$
(S) $${E}^{o}({Cr}^{3+},{Cr}^{2+})$$(4) $$-0.83V$$
View Solution
Q2
The standard reduction potential data at 25oC is given below:
Eo(Fe3+,Fe2+)=+0.77V;
Eo(Fe2+,Fe)=0.44V
Eo(Cu2+,Cu)=+0.34V;
Eo(Cu+,Cu)=+0.52V
Eo(O2(g)+4H++4e2H2O]=+1.23V;
Eo(O2(g)+2H2O+4e4OH)=+0.40V
Eo(Cr3+,Cr)=0.74V;
Eo(Cr2+,Cr)=0.91V;
Match Eo of the redox pair in List I with the values given in List II and select the correct answer using the code given below the lists.
List I List II
(P) Eo(Fe3+,Fe) (1) -0.18 V
(Q) Eo(4H2O4H++4OH) (2) -0.4 V
(R) Eo(Cu2++Cu2Cu+) (3) 0.04 V
(S) Eo(Cr3+,Cr2+) (4) -0.83 V


View Solution
Q3
The standard reduction potential data at 25oC is given below:

Eo(Fe3+,Fe2+)=+0.77V;
Eo(Fe2+,Fe)=0.44V
Eo(Cu2+,Cu)=+0.34V
Eo(Cu+,Cu)=+0.52V
Eo[O2(g)+4H++4e2H20]=+1.23V;
Eo[O2(g)+2H2O+4e40H]=+0.40V
Eo(Cr3+,Cr)=0.74V;
Eo(Cr2+,Cr)=0.91V
Match E0 of the redox pair in List 1 with the values given in List 2 and select the correct answer using the code given below the lists.
View Solution
Q4
The standard reduction potential data at 25ºC is given below.
Eo(Fe3+,Fe2+)=+0.77V;
Eo(Fe2+,Fe)=0.44V
Eo(Cu2+,Cu)=+0.34V;
Eo(Cu+,Cu)=+0.52V
Eo[O2(g)+4H++4e2H2O]=+1.23V;
Eo[O2(g)+2H2O+4e4OH]=+0.40V
Eo(Cr3+,Cr)=0.74V;
Eo(Cr2+,Cr)=0.91V
Match Eo of the redox pair in List I with the values given in List II and select the correct answer using the code given below the lists :
List I List-II
P. Eo(Fe3+,Fe) 1. 0.18 V
Q. Eo(4H2O4H++4OH) 2. 0.4 V
R. Eo(Cu2++Cu2Cu+) 3. 0.04V
S. Eo(Cr3+,Cr2+) 4. 0.83 V
P Q R S
(A) 4 1 2 3
(B) 2 3 4 1
(C) 1 2 3 4
(D) 3 4 1 2

View Solution
Q5

The standard reduction potential data at 25C is given below.

E(Fe3+/Fe2+)=0.77 V;E(Fe2+/Fe)=0.44V;E(Cu2+/Cu)=0.34 V;E(Cu+/Cu)=+0.52V;E(O2(g)+4H++4e)2H2O=+1.23V;E(O2(g)+2H2O+4e)4OH=+0.40VE(Cr3+/Cr)=0.74 V;E(Cr2+/Cr)=+0.91V

Match E of the rebox pair in Column I with the values given in Column II and select the correct answer using the code given below the lists.

Column IColumn IIP.E(Fe3+/Fe)1.0.18VQ.E(4H2O4H++4OH)2.0.4VR.E(Cu2++Cu2Cu+)3.0.04VS.E(Cr3+/Cr2+)4.0.83V


View Solution