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The statement which is always false is: \( ( \mathbf { p } \wedge \mathbf { q } ) \wedge \sim ( \mathbf { p } \vee \mathbf { q } \) \( \theta \vee ( \sim p \wedge q ) \) \( ( p \rightarrow q ) \rightarrow q \) \( \cup ( p \wedge q ) \wedge ( p \vee q \)

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