The steam point and the ice point of a mercury thermometer are marked as 80o and 20o. What will be the temperature in centigrade mercury scale when this thermometer reads 32o
20o
30o
10o
0o
A
0o
B
30o
C
20o
D
10o
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Solution
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From the relation:
T−2080−20=Tc100
where,
Tc is temperature in centigrate scale
T is the temperature measured by mercury thermometer and gives to be 32 degree
32−2080−20=Tc100
Tc=20°
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