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Updated on : 2022-09-05

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Correct option is A)

From the Einstein's photo electric equation, we get

$λhc =eV_{0}+ϕ$

$∴λhc =10.4eV+1.7eV$

$∴λhc =12.1eV$

$∴λ=12.1×1.6×10_{−19}hc $

$=12.1×1.6×10_{−19}6.63×10_{−34}×3×10_{8} $

$=1026A°$

Now, the transition between $3→1$

we get

$λ_{1}1 =R(1_{2}1 −3_{2}1 )=R(1−91 )$

$=98 R=98×1.097×10_{7} $

$∴λ=1026A°$

$∴$The energy level in hydrogen atom which will emit this wavelength is $n=3$ to $n=1$

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