0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

The string of a pendulum is horizontal initially. The mass of the bob attached is m. Now the string is released. 'R' is the length of the pendulum.
(i) Velocity of the string at an angle $$30^\circ$$ with the vertical is ________

A
$$\sqrt{\sqrt{2} gR}$$
B
$$\sqrt{\sqrt{3} gR}$$
C
$$\sqrt{\sqrt{5} gR}$$
D
$$\sqrt{\sqrt{7} gR}$$
Solution
Verified by Toppr

Correct option is B. $$\sqrt{\sqrt{3} gR}$$

Was this answer helpful?
0
Similar Questions
Q1
The string of a pendulum is horizontal initially. The mass of the bob attached is m. Now the string is released. 'R' is the length of the pendulum.
(i) Velocity of the string at an angle $$30^\circ$$ with the vertical is ________
View Solution
Q2
The string of a pendulum is horizontal initially. The mass of the bob attached is m. Now the string is released. 'R' is the length of the pendulum.
(i) The tension in the string at an angle 30 with the vertical is ______
View Solution
Q3
The string of a pendulum is horizontal initially. The mass of the bob attached is m. Now the string is released. 'R' is the length of the pendulum.
(i) Velocity of the string at the lowest point
View Solution
Q4
The string of a pendulum is horizontal. The mass of bob attached to it is m. Now the string is released. The tension in the string in the lowest position, is?
View Solution
Q5
A simple pendulum is released from rest with the string in horizontal position. The vertical component of the velocity of the bob becomes maximum, when the string makes an angle θ with the vertical. The angle θ is equal to
View Solution