The sum of digits of a two digit numbers is 11. If the digit at ten's place is increased by 5 and the digit at unit's place is decreased by 5, the digits of the number are found to be reversed. Find the original number.
83
28
82
38
A
83
B
28
C
82
D
38
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Solution
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The correct option is D38
Let the digits be x and y then:
x+y=11
(x+5)=y
∴x+(x+5)=11
⇒2x=11−5
⇒2x=6∴x=3
Nowy=11−3=8
Hence number is 38
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