The of squares of two consecutive odd whole numbers is 34- Find the numbers-

Question

Toppr Admin · Accepted Answer

Let the numbers be a-x2212-1-a-1-a-x2212-1-2-a-1-2-34a2-1-x2212-2a-a2-1-2a-342a2-2-342a2-32a2-16a-xB1-4-x2234- numbers are 4-x2212-1-4-1 or -x2212-4-x2212-1-x2212-4-13-5 or -x2212-5-x2212-3

The sum of squares of two consecutive odd whole numbers is $34$ . Find the numbers.

Let the numbers be $a - 1, a + 1$
${(a - 1)}^{2} + {(a + 1)}^{2} = 34 a^{2} + 1 - 2 a + a^{2} + 1 + 2 a = 34 2 a^{2} + 2 = 34 2 a^{2} = 32 a^{2} = 16 a = \pm 4$
$∴$ numbers are $4 - 1, 4 + 1$ or $- 4 - 1, - 4 + 1$
$3, 5$ or $- 5, - 3$

The sum of squares of two consecutive odd whole numbers is 34. Find the numbers.

Let the numbers be a−1,a+1(a−1)2+(a+1)2=34a2+1−2a+a2+1+2a=342a2+2=342a2=32a2=16a=±4∴ numbers are 4−1,4+1 or −4−1,−4+13,5 or −5,−3

The sum of squares of two consecutive odd whole numbers is $34$ . Find the numbers.

Let the numbers be $a - 1, a + 1$
${(a - 1)}^{2} + {(a + 1)}^{2} = 34 a^{2} + 1 - 2 a + a^{2} + 1 + 2 a = 34 2 a^{2} + 2 = 34 2 a^{2} = 32 a^{2} = 16 a = \pm 4$
$∴$ numbers are $4 - 1, 4 + 1$ or $- 4 - 1, - 4 + 1$
$3, 5$ or $- 5, - 3$