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Numbers in General Form
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The sum of squares of two consecutive od
Question
The sum of squares of two consecutive odd whole numbers is
$34$
. Find the numbers.
Easy
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Solution
Verified by Toppr
Let the numbers be
$a−1,a+1$
$(a−1)_{2}+(a+1)_{2}=34a_{2}+1−2a+a_{2}+1+2a=342a_{2}+2=342a_{2}=32a_{2}=16a=±4$
$∴$
numbers are
$4−1,4+1$
or
$−4−1,−4+1$
$3,5$
or
$−5,−3$
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