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Question

The sum of the digits of a 3 digit number is subtracted from the number. The resulting number is always
  1. divisible by 6
  2. not divisible by 6
  3. divisible by 9
  4. not divisible by 9

A
divisible by 9
B
divisible by 6
C
not divisible by 9
D
not divisible by 6
Solution
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Let three digit number be 100+10y+z
(100x+10y+z)(x+y+z)=99x+9y=9(11x+y)
which is already divided by 9.

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