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Question

The sum of the digits of a two digit number is 8. The digits of number get reversed when 18 is subtracted from the number. Find the original number.
  1. 32
  2. 62
  3. 53
  4. 71

A
32
B
62
C
53
D
71
Solution
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Let x= the 10s digit and y= be the unit digit
10x+y=original number
The sum of the digits of a two digit number is 8.
x+y=8.....(1)
The digits of number get reversed when 18 is subtracted from the original number.
Reversed digit = original number 18
10y+x=10x+y18
10yy=10xx18
9y=9x18
y=x2
Put the value of y in (1)
x+x2=8
2x=8+2
2x=10
x=102=5
x+y=8
5+y=8
y=85
y=3
Original number =53

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