The sum of the digits of a two-digit number is 9. If 9 is added to the number, then its digits interchange their place. What is the difference in cube of the digits?
65
61
89
125
A
89
B
125
C
61
D
65
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Solution
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Let the number be ab
Given sum of digits is 9⇒a+b=9...(1)
If 9 is added, its digits interchange which means ba
10a+b+9=10b+a
⇒9a+9=ab
⇒a−b=−1...(2)
From (1) & (2), a=4,b=5
∴ Diference in cube of digits =125−64
=61
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