The sum of three numbers is 98. If the ratio of the first to the second is 2:3 and that of the second to the third is 5:8, find the three numbers.
Let three numbers let a,b and c
A t.Q: a:b=2:3 and b:c=5:8
ab=23, bc=58
a=2b3, 5c=8b
c=8b5
∴ Sum of three numbers is 98
a+b+c=98
2b3+b+8b5=98
10b+15b+24b15=98
49b=1470
b=30
a=2×303c=8×305
a=20c=48
∴ The numbers are
20, 30 and 48