The sun and earth each exert a gravitational force on the Moon- what is the ration F-sun-F-Earth- of these two forces - The average Sun-Moon distance is equal to Sun-Earth distance-

Question

The sun and earth each exert a gravitational force on the Moon- what is the ration  F-sun-F-Earth-  of these two forces - The average Sun-Moon distance is equal to Sun-Earth distance-

Toppr Admin · Accepted Answer

We-160- use subscripts s-e- and m for the Sun- Earth and Moon- respectively- Plugging in the numerical values-160-160-we find-dfrac-F-sm-F-em-dfrac-Gm-s-m-m-r-2-sm-Gm-e-m-m-r-2-em-dfrac-m-s-m-e-left - -dfrac-r-em-r-sm- -right -2-160- -

The sun and earth each exert a gravitational force on the Moon. what is the ration $$ F_{sun}/F_{Earth} $$ of these two forces ( The average Sun-Moon distance is equal to Sun-Earth distance.)

We use subscripts s,e. and m for the Sun, Earth and Moon, respectively. Plugging in the numerical values
we find
$$\dfrac{F_{sm}}{F_{em}}=\dfrac{Gm_{s}m_{m}/r^{2}_{sm}}{Gm_{e}m_{m}/r^{2}_{em}}=\dfrac{m_{s}}{m_{e}\left ( \dfrac{r_{em}}{r_{sm}} \right )^{2}} $$

The sun and earth each exert a gravitational force on the Moon. what is the ration $$ F_{sun}/F_{Earth} $$ of these two forces ( The average Sun-Moon distance is equal to Sun-Earth distance.)

We use subscripts s,e. and m for the Sun, Earth and Moon, respectively. Plugging in the numerical values we find$$\dfrac{F_{sm}}{F_{em}}=\dfrac{Gm_{s}m_{m}/r^{2}_{sm}}{Gm_{e}m_{m}/r^{2}_{em}}=\dfrac{m_{s}}{m_{e}\left ( \dfrac{r_{em}}{r_{sm}} \right )^{2}} $$

We use subscripts s,e. and m for the Sun, Earth and Moon, respectively. Plugging in the numerical values
we find
$$\dfrac{F_{sm}}{F_{em}}=\dfrac{Gm_{s}m_{m}/r^{2}_{sm}}{Gm_{e}m_{m}/r^{2}_{em}}=\dfrac{m_{s}}{m_{e}\left ( \dfrac{r_{em}}{r_{sm}} \right )^{2}} $$