The t-1-2- of a radioactive substance is 100 sec- Its decay constant is- 6-93times 10-3-sec-1-6-93times10-1-sec-1-6-93 times 10-4-sec-1-6-93 times10-2-sec-1-

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Toppr Admin · Accepted Answer

T1-2-100-xA0-sec-xA0-x3BB-ln-xA0-2t1-2-0-693100-0-00693sec-x2212-1

$[A]$	$[B]$	Rate ( $M {min}^{- 1}$ )
$0.1$	$0.20$	$6.93 \times 10^{- 3}$
$0.1$	$0.25$	$6.93 \times 10^{- 3}$
$0.2$	$0.3$	$1.386 \times 10^{- 2}$

The $t$ $_{1 / 2}$ of a radioactive substance is $100 s e c$ . Its decay constant is:
$6.93 \times 10$ $^{- 3} s e c^{- 1}$
$6.93 \times 10$ $^{- 1} s e c^{- 1}$
$6.93 \times 10$ $^{- 4} s e c^{- 1}$
$6.93 \times 10$ $^{- 2} s e c^{- 1}$

$t_{1 / 2} = 100 s e c$

$λ = \frac{l n 2}{t_{1 / 2}} = \frac{0.693}{100}$ $= 0.00693 {s e c}^{- 1}$

The t1/2 of a radioactive substance is 100sec. Its decay constant is: 6.93×10−3sec−16.93×10−1sec−16.93×10−4sec−16.93×10−2sec−1

t1/2=100 sec λ=ln 2t1/2=0.693100=0.00693sec−1

The $t$ $_{1 / 2}$ of a radioactive substance is $100 s e c$ . Its decay constant is:
$6.93 \times 10$ $^{- 3} s e c^{- 1}$
$6.93 \times 10$ $^{- 1} s e c^{- 1}$
$6.93 \times 10$ $^{- 4} s e c^{- 1}$
$6.93 \times 10$ $^{- 2} s e c^{- 1}$

$t_{1 / 2} = 100 s e c$

$λ = \frac{l n 2}{t_{1 / 2}} = \frac{0.693}{100}$ $= 0.00693 {s e c}^{- 1}$