Question

Open in App

Verified by Toppr

Correct option is D)

$KAx $ and $2KA4x =KA2x $ respectively. Since the two resistors are in series, (as same heat current will flow through both), equivalent thermal resistance will be

$R_{eq.}=KAx +KA2x =KA3x $

Thus, heat current will be

$dtdQ =R_{eq.}T_{2}−T_{1} =31 xKA(T_{2}−T_{1}) $

Hence, $f=31 $

Solve any question of Thermal Properties Of Matter with:-

0

0