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Correct option is C)

In photoelectric effect, Einstein's equation is given by

Photon energy $=$ kinetic energy of electron $+$ work function

i.e. $hv=eV_{s}+hv_{0}$

where, $V_{s}$ is the stopping potential and $v_{0}$ is the threshold frequency.

$∴V_{s}=eh (v−v_{0})$ .....(i)

Given, $v_{0}=3.3×10_{14}Hz$, $v=8.2×10_{14}Hz$

$h=6.6×10_{−34}J−s$, $e=1.6×10_{−19}C$

Substituting these values in equation (i), we get

$V_{s}=1.6×10_{−19}6.6×10_{−34}(8.2×10_{14}−3.3×10_{14}) $

$V_{s}=1.66.6×4.9 ×10_{−1}=2V$

$⇒V_{s}=2V$

Solve any question of Dual Nature of Radiation And Matter with:-

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