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- 0.1 s
- 0.2 s
- 0.6 s
- 0.4 s

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Solution

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Time is zero at extreme position

T=1.2sec

v=ω√A2−x2;vmax=ωA

v=vmax2=ωA2=ω √A2−x2

A24=A2−x2;x=√32A

x=A cos ωt

√32A=A cos ωt

ωt=π6

t=π6×ω

t=/π6×1.22π/=0.1sec

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