0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

# The time period of oscillation of a particle that executes S.H.M. is 1.2sec. The time starting from extreme position, its velocity will be half of its velocity at mean position is 0.1 s0.2 s0.6 s0.4 s

A
0.1 s
B
0.2 s
C
0.4 s
D
0.6 s
Solution
Verified by Toppr

#### Time is zero at extreme positionT=1.2secv=ω√A2−x2;vmax=ωAv=vmax2=ωA2=ω √A2−x2A24=A2−x2;x=√32Ax=A cos ωt√32A=A cos ωtωt=π6t=π6×ωt=/π6×1.22π/=0.1sec

3
Similar Questions
Q1
The time period of oscillation of a particle that executes S.H.M. is 1.2sec. The time starting from extreme position, its velocity will be half of its velocity at mean position is
View Solution
Q2
The time period of oscillation of a particle, that executes SHM, is 1.2s. The time, starting from mean position, at which its velocity will be half of its velocity at mean position is ?
View Solution
Q3
The time period of oscillation of a particle in S.H.M. is π sec. If its acceleration at extreme position 1ms2, its velocity at mean position is
View Solution
Q4
A particle executes S.H.M. from extreme position and covers a distance equal to half of its amplitude in 1s. Determine the time period of motion.
View Solution
Q5
The time period of a particle performing S.H.M. is πs. It starts motion from the mean position. After π/6s, its velocity is 4cm/s. The amplitude is :
View Solution